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{-# OPTIONS -fbang-patterns #-}
-- compile as:
-- ghc --make -O2 -optc-O2 -fvia-C benchmarks.hs
-- ghc --make -O benchmarks.hs
import Numeric.LinearAlgebra
import System.Time
import System.CPUTime
import Text.Printf
import Data.List(foldl1')
time act = do
t0 <- getCPUTime
act
t1 <- getCPUTime
printf "%.3f s CPU\n" $ (fromIntegral (t1 - t0) / (10^12 :: Double)) :: IO ()
--------------------------------------------------------------------------------
main = sequence_ [bench1,bench2,bench3,bench4]
w :: Vector Double
w = constant 1 30000000
w2 = 1 * w
bench1 = do
putStrLn "Sum of a vector with 30M doubles:"
print$ vectorMax (w+w2) -- evaluate it
time $ printf " BLAS: %.2f: " $ sumVB w
time $ printf " Haskell: %.2f: " $ sumVH w
time $ printf " BLAS: %.2f: " $ sumVB w
time $ printf " Haskell: %.2f: " $ sumVH w
--time $ printf " innerH: %.2f: " $ innerH w w2
sumVB v = constant 1 (dim v) <.> v
sumVH v = go (d - 1) 0
where
d = dim v
go :: Int -> Double -> Double
go 0 s = s + (v @> 0)
go !j !s = go (j - 1) (s + (v @> j))
innerH u v = go (d - 1) 0
where
d = dim u
go :: Int -> Double -> Double
go 0 s = s + (u @> 0) * (v @> 0)
go !j !s = go (j - 1) (s + (u @> j) * (v @> j))
--------------------------------------------------------------------------------
bench2 = do
putStrLn "-------------------------------------------------------"
putStrLn "Multiplication of 1M different 3x3 matrices:"
-- putStrLn "from [[]]"
-- time $ print $ fun (10^6) rot'
-- putStrLn "from []"
time $ print $ manymult (10^6) rot
print $ cos (10^6/2)
rot' :: Double -> Matrix Double
rot' a = matrix [[ c,0,s],
[ 0,1,0],
[-s,0,c]]
where c = cos a
s = sin a
matrix = fromLists
rot :: Double -> Matrix Double
rot a = (3><3) [ c,0,s
, 0,1,0
,-s,0,c ]
where c = cos a
s = sin a
manymult n r = foldl1' (<>) (map r angles)
where angles = toList $ linspace n (0,1)
-- angles = map (k*) [0..n']
-- n' = fromIntegral n - 1
-- k = recip n'
--------------------------------------------------------------------------------
bench3 = do
putStrLn "-------------------------------------------------------"
putStrLn "foldVector"
let v = flatten $ ident 500 :: Vector Double
print $ vectorMax v -- evaluate it
let getPos k s = if k `mod` 500 < 200 && v@>k > 0 then k:s else s
putStrLn "indices extraction, dim=0.25M:"
time $ print $ (`divMod` 500) $ maximum $ foldLoop getPos [] (dim v)
putStrLn "sum, dim=30M:"
--time $ print $ foldLoop (\k s -> w@>k + s) 0.0 (dim w)
time $ print $ foldVector (\k v s -> v k + s) 0.0 w
putStrLn "sum, dim=0.25M:"
--time $ print $ foldVector (\k v s -> v k + s) 0.0 v
time $ print $ foldLoop (\k s -> v@>k + s) 0.0 (dim v)
-- foldVector is slower if it is used in two places. (!?)
-- this does not happen with foldLoop
foldLoop f s d = go (d - 1) s
where
go 0 s = f (0::Int) s
go !j !s = go (j - 1) (f j s)
foldVector f s v = foldLoop g s (dim v)
where g !k !s = f k (v@>) s
--------------------------------------------------------------------------------
bench4 = do
putStrLn "-------------------------------------------------------"
putStrLn "1000x1000 inverse"
let a = ident 1000 :: Matrix Double
let b = 2*a
print $ vectorMax $ flatten (a+b) -- evaluate it
time $ print $ vectorMax $ flatten $ linearSolve a b
|
